Course Dependency

mediumcodingAlgorithmsGraphs

Overview

You are given numCourses courses labeled from 0 to numCourses - 1, and an array prerequisites where prerequisites[i] = [a, b] means you must take course b before course a.

Return true if it is possible to finish all courses, or false if there is a circular dependency.

Constraints

  • 1 <= numCourses <= 2000
  • 0 <= prerequisites.length <= 5000
  • prerequisites[i].length === 2
  • 0 <= prerequisites[i][0], prerequisites[i][1] < numCourses
  • All prerequisite pairs are unique.

Examples

canFinish(2, [[1, 0]]);
// => true  (take course 0 first, then course 1)
canFinish(2, [[1, 0], [0, 1]]);
// => false  (circular dependency)

canFinish(4, [[1, 0], [2, 1], [3, 2]]);
// => true  (linear chain: 0 -> 1 -> 2 -> 3)

Solution

Reveal solution
function canFinish(numCourses, prerequisites) {
  const adj = Array.from({ length: numCourses }, () => []);
  const inDegree = new Array(numCourses).fill(0);

  for (const [a, b] of prerequisites) {
    adj[b].push(a);
    inDegree[a]++;
  }

  const queue = [];
  for (let i = 0; i < numCourses; i++) {
    if (inDegree[i] === 0) queue.push(i);
  }

  let completed = 0;
  while (queue.length > 0) {
    const course = queue.shift();
    completed++;
    for (const next of adj[course]) {
      inDegree[next]--;
      if (inDegree[next] === 0) queue.push(next);
    }
  }

  return completed === numCourses;
}

Kahn's algorithm for topological sort. If we can process all nodes, there's no cycle.

Resources

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